Java 教程

Java 实例 - 利用堆栈将中缀表达式转换成后缀表达式

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以下实例演示了如何使用堆栈进行表达式的堆栈将中缀(Infix)表达式转换成后缀(postfix)表达式:

InToPost.java 文件

import java.io.IOException; public class InToPost { private Stack theStack; private String input; private String output = ""; public InToPost(String in) { input = in; int stackSize = input.length(); theStack = new Stack(stackSize); } public String doTrans() { for (int j = 0; j < input.length(); j++) { char ch = input.charAt(j); switch (ch) { case '+': case '-': gotOper(ch, 1); break; case '*': case '/': gotOper(ch, 2); break; case '(': theStack.push(ch); break; case ')': gotParen(ch); break; default: output = output + ch; break; } } while (!theStack.isEmpty()) { output = output + theStack.pop(); } System.out.println(output); return output; } public void gotOper(char opThis, int prec1) { while (!theStack.isEmpty()) { char opTop = theStack.pop(); if (opTop == '(') { theStack.push(opTop); break; } else { int prec2; if (opTop == '+' || opTop == '-') prec2 = 1; else prec2 = 2; if (prec2 < prec1) { theStack.push(opTop); break; } else output = output + opTop; } } theStack.push(opThis); } public void gotParen(char ch){ while (!theStack.isEmpty()) { char chx = theStack.pop(); if (chx == '(') break; else output = output + chx; } } public static void main(String[] args) throws IOException { String input = "1+2*4/5-7+3/6"; String output; InToPost theTrans = new InToPost(input); output = theTrans.doTrans(); System.out.println("Postfix is " + output + 'n'); } class Stack { private int maxSize; private char[] stackArray; private int top; public Stack(int max) { maxSize = max; stackArray = new char[maxSize]; top = -1; } public void push(char j) { stackArray[++top] = j; } public char pop() { return stackArray[top--]; } public char peek() { return stackArray[top]; } public boolean isEmpty() { return (top == -1); } } }

以上代码运行输出结果为:

124*5/+7-36/+
Postfix is 124*5/+7-36/+

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