题目:输入某年某月某日,判断这一天是这一年的第几天?
程序分析:以3月5日为例,应该先把前两个月的加起来,然后再加上5天即本年的第几天,特殊情况,闰年且输入月份大于2时需考虑多加一天:
程序源代码:
实例(Python 2.0+)
#!/usr/bin/python
# -*- coding: UTF-8 -*-
year = int(raw_input('year:n'))
month = int(raw_input('month:n'))
day = int(raw_input('day:n'))
months = (0,31,59,90,120,151,181,212,243,273,304,334)
if 0 < month <= 12:
sum = months[month - 1]
else:
print 'data error'
sum += day
leap = 0
if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)):
leap = 1
if (leap == 1) and (month > 2):
sum += 1
print 'it is the %dth day.' % sum
以上实例输出结果为:
year: 2015 month: 6 day: 7 it is the 158th day.其他扩展