Python 数组翻转指定个数的元素

def leftRotate(arr, d, n):
for i in range(d):
leftRotatebyOne(arr, n)
def leftRotatebyOne(arr, n):
temp = arr[0]
for i in range(n-1):
arr[i] = arr[i+1]
arr[n-1] = temp


def printArray(arr,size):
for i in range(size):
print ("%d"% arr[i],end=" ")


arr = [1, 2, 3, 4, 5, 6, 7]
leftRotate(arr, 2, 7)
printArray(arr, 7)

def leftRotate(arr, d, n):
for i in range(gcd(d,n)):

temp = arr[i]
j = i
while 1:
k = j + d
if k >= n:
k = k - n
if k == i:
break
arr[j] = arr[k]
j = k
arr[j] = temp

def printArray(arr, size):
for i in range(size):
print ("%d" % arr[i], end=" ")

def gcd(a, b):
if b == 0:
return a;
else:
return gcd(b, a%b)

arr = [1, 2, 3, 4, 5, 6, 7]
leftRotate(arr, 2, 7)
printArray(arr, 7)

def rverseArray(arr, start, end):
while (start < end):
temp = arr[start]
arr[start] = arr[end]
arr[end] = temp
start += 1
end = end-1

def leftRotate(arr, d):
n = len(arr)
rverseArray(arr, 0, d-1)
rverseArray(arr, d, n-1)
rverseArray(arr, 0, n-1)

def printArray(arr):
for i in range(0, len(arr)):
print (arr[i], end=' ')

arr = [1, 2, 3, 4, 5, 6, 7]
leftRotate(arr, 2)
printArray(arr)